📄 07 - SET-4 (Trains Advanced), p.9
A train of length 200m, traveling at 80 km/h, overtakes a motorcyclist traveling in the same direction at a speed of 20 km/h at 11:00 am. At 1:00 pm, it overtakes another cyclist traveling in the same direction at a speed of 10 km/h. At what time will the motorcyclist overtake the cyclist?
(A) 1:00 am
(B) 3:00 am
(C) 11:00 pm
- Finally, both the motorcyclist and the cyclist would be at 1 P.M. before you find their meeting time (1 A.M.).
A train running at 65 km/h crosses a tunnel that is double its length in 1 minute 30 seconds. In how much time would it cross another train, which is half of its length and coming from the opposite direction at 32.5 km/hr?
(A) 45 seconds
(B) 1 minute 15 seconds
(C) 25 seconds
==(D) 30 seconds ==
(E) 50 seconds
- When you have keywords like double or half in the question, use the table method below. The S,D,T units at the top of the table should be placed in the same order as given in the question.
- Use 90s as a reference and apply the chain rule to it.
- Times increase from 65 to 97.5.
- Times decrease from 3 to 1.5.
Two trains running in opposite directions cross a man standing on the platform in 54 seconds and 34 seconds, and they cross each other in 46 seconds. Find the ratio of their speeds.
(A) 3:2
(B) 2:3
(C) 5:3
(D) 3:5
- In the Alligation method, the Time Ratio is automatically inversed to the Speed Ratio.
- If the Ratio of Speeds is asked in the question, use the Alligation method. In the Alligation method, write the respective trains passing Time Ratio data in the same order as given in the question. Cross-verify that the Average Time value falls between the above Time values.
Two trains running in opposite directions cross a man standing on the platform in 25 seconds and 32 seconds respectively, and they cross each other in 30 seconds. The ratio of their speeds is:
(A) 4:3
(B) 2:5
(C) 5:6
(D) 1:3